In a fort 300 men had provisions for 90 days

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WebAnswer (s) Ans 1= 120 Men - 195 days (provision left after 5 days) 30 men killed Men left - 90 Days - D so 120 x 195 = 90 x D D= 260 days Ans 2= 1200 soldiers - 24 days (after 4 days) soldiers leaving= S days= 32 so (1200-S) x 32 = 1200 x 24 S =300 soldiers By: Niharika, 1 decade ago 3 like this answer consider 1 person consumes "X" food per day WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? A 88 days B 48 days C 84 days D 44 days Medium …

A fort has provision for 50 days. If after 10 days they are ... - Toppr

WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? (www.math-only-math.com) Solution: Remaining number of men = (300 - 50) = 250. Remaining number of days = (90 - 20) days = 70 days. 300 men had provisions for 70 days WebApr 4, 2024 · It is given that 150 men had food for 45 days. After 10 days, 150 men still had food for 35 days. Since, 25 men left the fort so $150 - 25 = 125$ men are left in the fort. Now, let us suppose that 125 men had food for the x number of days. We know that we have the case of indirect proportion here because as the number of men will decrease food ... how to remove rust from rifle bore

A Group of 120 Men Had Provisions For 200 Days After 5 Days

WebIn a fort 150 men had provisions for 45 days. After 10 days, 25 men left the fort. How long would the food last at the same rate? Advertisement Remove all ads. Solution Show Solution. After 10 days : For 150 men, provision will last (45 − 10) days = 35 days. WebA fort had provisions with 300 men for 90 days. After 20 days 50 men left the fort. How long would the food last at the same rate? Question: A fort had provisions with 300 men for 90 … WebA fort is provisioned for 42 days; after 10 days, a reinforcement of 200 men arrives and the food will now last only for 24 days. How many men were there in the fort ? A 400 B 500 C 600 D 160 Medium Solution Verified by Toppr Correct option is C) let there be N men in the fort initially. Let one person eat an amount equal to V in a day. how to remove rust from pool water

A garrion had provisions for 1500 men for 30 days. After some days, 300 …

In a Fort, 300 soldiers had of food provision for 90 days. after 20

WebRight Answer is: SOLUTION First statement says that 300 men has 90 days food so total is 300*90=2700 After 20 days 50 men left that is 250 men still there and 70 days food of … WebJan 13, 2024 · A fort has provisions for 300 men for 90 days . After 20 days , 50 men left the fort . How long would the food last at the same rate ? Advertisement Answer 3 people found it helpful tanunagar21 Answer: 84 Step-by-step explanation: Remaining number of men = (300−50)=250. Remaining number of days = (90−20)days=70 days normal methane levels in sibo breath test how to remove rust from rifle

"WebMay 18, 2016 · A fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate. So men is inversely proportional to … " - In a fort 300 men had provisions for 90 days

In a fort 300 men had provisions for 90 days

A fort had provisions of food for 300 men for 90days, after 20 days…

WebA man can do a work in 3 days alone and a women can do the same work in 9 days alone. If both are work together in how many days they finished the same work. There are 8 mango … WebAfter some days, 300 more men joined the gar... - YouTube A garrison had provisions for 1500 men for 30 days. After some days, 300 more men joined the garrison. The provisions...

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WebWe know that no. of days is inversely proportional to the provision for men. So for 120 men the provision would last for 30 days (given) Therefore, the provision for 1 men would sustain for 120 × 30 = 3600 d a y s Let after the joining of 5 men (after 5 days) the no of more days the provision would last is x days. 120 × 30 = 120 × 5 + 125 × x WebAug 2, 2016 · First 90 days were there but at present days are left 90-20= 70 days. There were 300 men but 50 men then left, Remaining one's= 300-50= 250 men. So, provision for …

WebNov 2, 2024 · In a fort, there are 1500 soldiers and they have provisions for 90 days.If 600 soldiers leave the fort and the remaining soldiers increase their consu askedNov 2, 2024in Mathematicsby Dhruvan(88.7kpoints) class-8 time-and-work-pipes-and-cisterns 0votes 1answer In a garrison of 10 soldiers, there was enough food to last for 28 days. WebA fort had provisions with 300 men for 90 days. After 20 days 50 men left the fort. How long would the food last at the same rate? Question: A fort had provisions with 300 men for 90 days. After 20 days 50 men left the fort. How long would the food last at the same rate?

WebMar 9, 2014 · A fort has provisions for 300 men for 90 days.After 20 days, 50 men left the the fort then how long would the provisions last at the same rate? WebMar 8, 2014 · in a fort 300 men had provision for 90 days after 20 days,50 men left the fort how long would the food last,at the same rate - Maths - NCERT Solutions Board Paper …

WebFeb 22, 2024 · Solution For In a fort , 300 men had provisions for 90 days. After 20 days, 50 men left the fort. How long would the provisions last at the same rate?

WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? Class:8 PhipsArt Almost yours: 2 weeks, on us... how to remove rust from panWebRight Answer is: SOLUTION First statement says that 300 men has 90 days food so total is 300*90=2700 After 20 days 50 men left that is 250 men still there and 70 days food of 300 men is available so total food available for 250 men is 300*70/250= 84 days . So 250 men can have food for 84 days . how to remove rust from power toolsWebSolution Verified by Toppr Correct option is C) Let there be x men originally. So, x men had provisions 40 days whereas (x+500) men consumed it in 35 days Let us find the number of men in the fort as shown below: xx+500= 3540 ⇒ xx+500= 78⇒7(x+500)=8x ⇒7x+3500=8x ⇒8x−7x=3500 ⇒x=3500 Hence, there are 3500 men in the fort. Was this answer helpful? 0 0 how to remove rust from refrigeratorWebGiven: In a Fort, 300 soldiers had of food provision for 90 days. After 20 days, 50 soldiers left the Fort, So, the remining soldiers 250 had the food for x days. As soldiers increases the … how to remove rust from razor bladesWebAug 19, 2024 · Answer: Step-by-step explanation: 300 men had provision for 90 days let total quantity of provisions be x if 300 men take 90 days to finish x food then 1 man in 1 day will finish x/ (300*90) food thus 300 men in 20 days will finish x/ (300*90) * 300 *20 food = 2x/9 food food left = x - 2x/9 = 7x/9 now 300- 50 = 250 normal methb in adultsWebMar 2, 2024 · First 90 days were there but at present days are left 90-20= 70 days There were 300 men but 50 men then left, Remaining one's= 300-50= 250 men So, provision for 300 men= 70 days Provision for 250 men will be = x As its indirect variation, so formula 70/x= 250/300 70×300/250= x 2100/25= x 420/5= x Hope my answer help you. My pleasure how to remove rust from potsWebA garrison of 500 men had provisions for 24 days. However, a reinforcement of 300 men arrived. The food will now last for (a) 18 days (b) 17 1 2 days (c) 16 days (d) 15 days. Q. In a garrision 500 men had provision for 60 days. A reinforcement of 500 men arrived. ... Q. A fort provisioned for 42 days, after 10 days, a reinforcement of 200 men ... how to remove rust from rotor hub